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The perimeter of a trapezium is 104 cm, ...

The perimeter of a trapezium is 104 cm, the lengths of its non-parallel sides are 18 cm and 22 cm and its altitude is 16 cm. The area (in `cm^(2)`) of the trapezium is

A

1024

B

640

C

512

D

320

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AI Generated Solution

The correct Answer is:
To find the area of the trapezium given the perimeter, lengths of the non-parallel sides, and the altitude, we can follow these steps: ### Step 1: Understand the given information - Perimeter of trapezium (P) = 104 cm - Length of non-parallel sides = 18 cm and 22 cm - Altitude (height) = 16 cm ### Step 2: Set up the equation for the perimeter The perimeter of a trapezium is the sum of the lengths of all its sides. If we denote the lengths of the parallel sides as \( a \) and \( b \), we can write the equation for the perimeter as: \[ P = a + b + 18 + 22 \] Substituting the given perimeter: \[ 104 = a + b + 40 \] ### Step 3: Solve for the sum of the parallel sides Rearranging the equation to find \( a + b \): \[ a + b = 104 - 40 = 64 \text{ cm} \] ### Step 4: Use the area formula for the trapezium The area \( A \) of a trapezium can be calculated using the formula: \[ A = \frac{1}{2} \times (a + b) \times \text{height} \] Substituting the values we have: \[ A = \frac{1}{2} \times 64 \times 16 \] ### Step 5: Calculate the area Now, we calculate the area: \[ A = \frac{1}{2} \times 64 \times 16 = 32 \times 16 = 512 \text{ cm}^2 \] ### Final Answer The area of the trapezium is \( 512 \text{ cm}^2 \). ---
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