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When 2 g of a gas A is introduced into a...

When `2 g` of a gas `A` is introduced into an evacuated flask kept at `25^(@)C`, the pressure is found to be `1 atm`. If `3 g` of another gas `B` is then heated in the same flask, the total pressure becomes `0.5 atm`. Assuming ideal gas behaviour, calculate the ratio of the molecular weights `M_(A)` and `M_(B)`.

A

`1 :3`

B

`3:1`

C

`2:3`

D

`3:2`

Text Solution

Verified by Experts

The correct Answer is:
A
Moles `prop` Pressure
`(2)/(Mw_(A)) prop 1 "atm"`
Pressure of `B = 1.5 - 1 = 0.5 "atm"`
`(3)/(Mw_(B)) prop 0.5 "atm"`
`(3)/(Mw_(B)) xx (Mw_(A))/(2) = (0.5)/(1)`
`(MW_(A))/(Mw_(B)) = 0.5 xx (2)/(3) = (1)/(3)`
`(Mw_(A) : Mw_(B) = 1:3`
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