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How much U^(235) is consumed in a day in...

How much `U^(235)` is consumed in a day in an atomic power house operating at 400 MW, provided the whole of the mass of `U^(235)` is converted into energy?

Text Solution

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Power = 400 MW = `400 xx10^(6)W,`
time = 1 day = 86 , 400 s.
Energy produced , E = power `xx ` time
`=400xx10^(6)xx86,400=3.456xx10^(13)J`
As the whole of mass is converted into energy , by Einstein.s mass - energy relation `E =Mc^2`
`M = E/(c^2) = (3.456xx10^(13))/((3xx10^(8))^2) =3.84xx10^(-4)kg = 0.384 g`.
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