Balmer gave an equation for wavelength of visible region of H-spectrum as `barv =(n^2 - 4)/(Kn^2)` where n = principal quantum number of energy level, K = constant terms.of R (Rydberg constant). The value of K in terms of R is:
A
R
B
`R/2`
C
`4/R`
D
`5/R`
Text Solution
Verified by Experts
Topper's Solved these Questions
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise Level- 1|1 Videos
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise level 2|1 Videos
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 2|1 Videos
Similar Questions
Explore conceptually related problems
Which of the following expressions represents the spectrum of Balmer series (If n is the principal quantum number of higher energy level) in Hydrogen atom?
(A) Balmer series lies in the visible region of electromagnetic spectrum (R): (1)/(lambda) = R((1)/(2^(2)) - (1)/(n^(2))) where n = 3,4,5
In case of hydrogen spectrum wave number is given by barv = R_H [(1)/(n_2^2) - 1/(n_2^2)] where n_1 lt n_2
Excited atoms emit radiations consisting of only certain discrete frequencies or wavelengths. In spectroscopy it is often more convenient to use frequencies or wave numbers than wavelength because frequencies and wave numbers are proportional to energy and spectroscopy involves transitions between different energy levels. The line spectrum shown by a mono electronic excited atom (a finger print of an atom) is called atomic spectrum. 1/(lambda) = Z^2 R [1/(n_1^2 - 1/(n_2^2)] The given diagram indicates the energy levels of certain atom. When an electron moves from 2E level to E level, a photon of wavelength lambda is emitted. The wavelength of photon emitted during its transition from (4E)/(3) level to E level is
An excited hydrogen atom emits a photon of wavelength t while returning to the ground state. If R is the Rydberg.s constant, then the quantum number n of the excited state is
A hydrogen atom emits a photon of wavelength 36/(35R) when it is jumped from its nth excited state to the ground state. Then the quantum number n is (R is Rydberg constant.)
The letters n, l and m proposed by Bohr, Sommerfeld and Zeeman respectivelt for quantization of angular momentum in classical physics were later on obtained as the results of solution of Schrodinger wave equation based on quantum mechanics. The term n, l, m are named as principal quantum number, azimuthal quantum number and magnetic number respectively. The fourth quantum number i.e., spin quantum number (s) was given by Uhlenback on the basis of two spins of electrons. The first two quantum number also decides the nodes of an orbital. Which statement about energy level in H-atom is correct ?
