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Three 2 Omega resistors, A, B and C are ...

Three `2 Omega` resistors, A, B and C are connected as shown in figure. Each of them dissipates energy and can with stand a maximum power of 18 W without melting. Find the maximum current that can flow through the three resistors ?

Text Solution

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`P=I^(2)R`
`A=sqrt(18/2)A=3A`
Thus the maximum current through resistors B and C as they are connected in parallel, each
`3xx1/2 A=1.5 A`
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