The respective ages of a father and his son are 41 and 16 years. In how many years will the father be twice as old as his son ?

Options

A. 19 years
B. 9 years
C. 10 years
D. 15 years

Answer

To solve the problem, we need to set up an equation based on the information given about the ages of the father and son.

1. **Current Ages**:
- Father's age = 41 years
- Son's age = 16 years

2. **Let T be the number of years from now** when the father will be twice as old as his son.

3. **Express the future ages**:
- Father's age after T years = 41 + T
- Son's age after T years = 16 + T

4. **Set up the equation**:
We want to find T such that the father's age is twice the son's age:
\[ 41 + T = 2(16 + T) \]

5. **Expand the equation**:
\[ 41 + T = 32 + 2T \]

6. **Rearranging the equation**:
Subtract T from both sides:
\[ 41 = 32 + T \]
Now, subtract 32 from both sides:
\[ 41 - 32 = T \]
\[ T = 9 \]

7. **Conclusion**:
In 9 years, the father will be twice as old as his son.