A particle moves along a straight line such that its velocity (v) at any time `(t)` is given by `v=(2t-1)m/s` where `t` is in seconds. Total distance travelled by the particle in first second is

The velocity 'v' of a particle moving along straight line is given in terms of time t as v=3(t^(2)-t) where t is in seconds and v is in m//s . The distance travelled by particle from t=0 to t=2 seconds is :

The position of a particle along x-axis at time t is given by x=1 + t-t^2 . The distance travelled by the particle in first 2 seconds is

The displacement of a particle is moving by x = (t - 2)^2 where x is in metres and t in second. The distance covered by the particle in first 4 seconds is.

The displacement of a particle is moving by x = (t - 2)^2 where x is in metres and t in second. The distance covered by the particle in first 4 seconds is.

A particle moves along a straight line its velocity dipends on time as v=4t-t^(2) . Then for first 5 s :

A particle is moving in a straight line such that its distance s at any time t is given by s=(t^4)/4-2t^3+4t^2-7. Find when its velocity is maximum

A particle moves along a staight line such that its displacement at any time t is given by s=t^3-6t^2+3t+4m . Find the velocity when the acceleration is 0.

A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is

A particle moves along a horizontal path, such that its velocity is given by v = (3t^2 - 6t) m//s, where t is the time in seconds. If it is initially located at the origin O, determine the distance travelled by the particle in time interval from t = 0 to t = 3.5 s and the particle's average velocity and average speed during the same time interval.

A particle is moving in a striaght line and at a given time, its displacement is S = t^(3) - 6t^(2) + 9t , where t is in seconds and S is in meter . The total distance travelled by the particle during the first five seconds is