`2x+3y=4`,`2x-3y=2`

Find A^(-1), where A=[1 2-3 2 3 2 3-3-4] . Hence solve the system of equations: x+2y-3z=-4,2x+3y+2z=2 , 3x-3y-4z=11

{:(3x + 2y = 4),(2x - 3y = 7):}

Prove that the lines 2x-3y+1=0,\ x+y=3,\ 2x-3y=2\ a n d\ x+y=4 form a parallelogram.

Solve: {:(2x + 3y = 4),(x - y = - 3):}

Find the continued product: (2x+3y)(2x-3y)(4x^2+9y^2)

The latusrectum of the parabola 13[(x-3)^(2)+(y-4)^(2) ]= (2x-3y+5)^(2)

If A=[(1,2,-3),(2,3,2),(3,-3,-4)] then find A^-1 and hence solve the follwoing equations: x+2y-3z=4, 2x+3y+2z=2 and 3x-3y-4z=11

Prove that |{:(x,x+y,x+y+z),(2x,3x+2y,4x+3y+2z),(3x,6x+3y,10x+6y+3z):}|=x^3

If |[x,x+y, x+y+z],[2x,3x+2y,4x+3y+2z],[3x,6x+3y, 10 x+6y+3z]|=64 , then the real value of x is __________.

If |(x, x+y, x+y+z),(2x,3x+2y, 4x+3y+2z),(3x,6x+3y, 10x+6y+3z)|=64 then the real value of x is