Uniform ring of radius R is moving on a horizontal surface with speed v and then climbs up a ramp of inclination `30^(@)` to a height h. There is no slipping in the entire motion. Then h is

Options

A. `v^(2)//2g`
B. `v^(2)//g`
C. `3v^(2)//2g`
D. `2v^(2)//g`

Answer

B

Explanation

`mgh= (1)/(2) mv^(2) + (1)/(2) mR^(2) ((v^(2))/(R^(2))) = mv^(2) rArr h= (v^(2))/(g)`