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A coil carrying a current 'I' has r...

A coil carrying a current 'I' has radius 'r' and number of turns 'n' it is rewound so that radius of the new coil is `(r )/(4)` and it carries current `I' The ratio of the magnetic moment of the new coil to that of the original coil is

A

1

B

`(1)/(2)`

C

`(1)/(4)`

D

`(1)/(8)`

Text Solution

Verified by Experts

The correct Answer is:
C

`M_(1) = nI (pi r^(2))`
now, n (`2pi r) = n. (2pi "" ( r)/(4)) implies n. = 4n`
`M_(2) = 4nl [ pi ((r^2)/(4))^(2)] = (M_(1))/(4)`
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