In the circuit shown in figure, if the A diode forward voltage drop is 0.3 V, the voltage difference between A and B is

Options

A. `1.3` V
B. `2.3` V
C. `0`
D. `0.5` V

Answer

B

Explanation

Consider the figure given here suppose the potential difference between A and B is V and `r_(1)=5kOmega`, `r_(2)=5kOmega` are resistances in series connection.

Then,
`V-0.3=[(r_(1)+r_(2))10^(3)]xx(0.2xx10^(-3))]` [`:.V=ir]`
`=[(5+5)10^(3)]xx(0.2xx10^(-3))`
`=10xx10^(3)xx0.2xx10^(-3)=2impliesV=2+0.3=2.3V`.