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On the basis of following equations the ...

On the basis of following equations the heat of dimerisation of `NO_(2)` will be
(i) `N_(2)+2O_(2)rarr2NO_(2) " "DeltaH=67.9 kJ`
(ii) `N_(2)+2O_(2)rarrN_(2)O_(4) " "DeltaH=09.3 kJ`

A

`+77.2kJ`

B

`-77.2kJ`

C

`-58.6kJ`

D

`+58.6kJ`

Text Solution

Verified by Experts

The correct Answer is:
C
So Heat of dimerisation of `2NO_(2) rarr N_(2)O_(4)` ...(iii)
Given
`2NO_(2) rarr N_(2) + 2O_(2) Delta H= -67.9kJ` ....(i)
`N_(2)O_(4) rarr N_(2) + 2O_(2) Delta H= -09.3 kJ` ...(ii)
On subtracting equation (ii) from (i) we will get equation (iii)
`2NO_(2)- N_(2)O_(4) rarr 0`
`2NO_(2) rarr N_(2)O_(4)` ..(iii)
So Heat of dimerisation of `NO_(2)= -67.9- (-09.3)kJ= -67.9+ 9.3= -58.6kJ`
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