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The standard Gibb's free energy change, ...

The standard Gibb's free energy change, `DeltaG^(@)` is related to equilibrium constant, kp as

A

`K_(p)= - RT ln Delta G^(@)`

B

`K_(p)= ((e)/(RT))^(Delta G^(@))`

C

`K_(p)= - (Delta G^(@))/(RT)`

D

`K_(p)= e^(-(Delta G^(@))/(RT))`

Text Solution

Verified by Experts

The correct Answer is:
D

`K_(p)= e^(-Delta G^(@)//RT)`
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