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NH(4)HS(s) hArr NH(3)(g)+H(2)S(g) In t...

`NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g)`
In the above reaction, if the pressure at equilibrium and at 300K is 100atm then what will be equilibrium constant `K_(p)` ?

A

`2500 "atm"^2`

B

`50 "atm"^2`

C

`100 "atm"^2`

D

`200 "atm"^2`

Text Solution

Verified by Experts

The correct Answer is:
A

`NH_4HS(s) hArr NH_3 (g) +H_2S(g)`
`{:(1,0,0 "initially"),(1-alpha,alpha,alpha" at equilibrium"):}`
According to question at the equilibrium
`alpha + alpha = 100 implies alpha =50 ` atm
`:. K_p P_(NH_3) xx P_(H_2S) = 50 xx50 = 2500 " atm"^2`
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