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The electron of a hydrogen atom revolves...

The electron of a hydrogen atom revolves the proton in a circuit nth of radius `r_(0) = (in_(0) n^(2)h^(2))/(pi m e^(2)) ` with a speed `upsilon_(0) =(e^(2))/(2 in_(0) nh)` The current the to circulating charge is proportional to

A

`e^2`

B

`e^3`

C

`e^5`

D

`e^6`

Text Solution

Verified by Experts

The correct Answer is:
C
`T=(2pir_n)/v_n= (2pixxepsilon_0n^2h^2)/(pi me^2) xx(2epsilon_0nh)/(e^2) = (4 epsilon_0^2n^3h^3)/(me^4)`
Current `(I_n)=q/T=e/((4epsilon_0^2n^3h^3)/(me^4))=(me^5)/(4epsilon_0^2n^3h^3)`
`I_n prop e^5`
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