A balloon starts rising from the ground with an acceleration of `1.25ms^-2`. After 8 seconds, a

A balloon starts rising from the ground with an acceleration 2 ms^(-2) . After 5 second , a stone is released from the ballooon. Find the time taken by the stone to reach the ground after its release and total height attained by ballooon when stone reaches the ground. Take g==10 ms^(-2) .

A balloon starts rising from ground with an acceleration of 1.25 m//sec^2 . A 8 seconds a stone is released from the balloon. The maximum height from the ground reached by stone will be.

A balloon starts rising from the ground with a constant acceleration of 1.25m//s^(2) . After 8 s, a stone is released from the balloon. Find the time taken by the stone to reach the ground. (Take g=10m//s^(2) )

A balloon starts rising from the ground with an acceleration of 1.25 m//s^(2) . A stone is released from the balloon after 10s. Determine (1) maximum height of ston from ground (2) time taken by stone to reach the ground

A balloon starts rising from ground from rest with an upward acceleration 2m//s^(2) . Just after 1 s, a stone is dropped from it. The time taken by stone to strike the ground is nearly

A ballon starts risintg from ground from rest at some constant acceleration. After some time, a storne is dropped from it. If the stone reaches the ground in the same time in which balloon reached the dropping poing from ground, find the acceleration of the balloon.

A balloon of mass m is rising up with an acceleration a.

A balloon starts rising upwards with constant acceleration a and afrer time t_(0) , second, a packet is dropped from it which reaches the ground aftre t seconds of dropping . Derermine the value of t .

A balloon starts from the state of rest from the ground with constant acceleration g/n. after time T, a stone is dropped from the balloon. If stone takes time T to reach the ground then calculate value of n.