[" 37.A right circular cone is divided into two portions by a plane parallel to the base "],[" and passing through a point,which is "1/3" of the height from the top.Find the ratio of "],[" the smaller cone to that of the remaining frustum of the cone."]

A right circular cone is divided into two portions by a plane parallel to the base and passing through a point which is (1)/(3)rd of the height from the top.The ratio of the volume of the smaller cone to that of the remaining frustum of the cone is (a) 1: 3(b) 1: 9 (c) 1:26 (d) 1:27

The slant height of a right circular cone is 10 cm and its height is 8 cm. It is cut by a plane parallel to its base passing through the midpoint of the height. Ratio of the volume of the cone to that of the frustum of the cone cut is

A right circular cone is divided by a plane parallel to its base in two equal volumes. In what ratio will the plane divide the axis of the cone?

A right circular cone is divided by a plane parallel to its base in two equal volumes. In what ratio will the plane divide the axis of the cone?

A right circular cone is cut by two planes parallel to the base and trisecting the height. Compare the volumes of three parts into which the cone is divided.

A solid right circular cone is cut into two parts at the middle of its height by a plane parallel to its base . The ratio of the volume of the smaller cone to the whole cone is

The height of a right circular cone is trisected by two planes drawn parallel to the base. Show that the volumes of the three portions starting from the top are in the ratio 1:7:19.

The height of a right circular cone is trisected by two planes drawn parallel to the base. Show that the volumes of the three portions starting from the top are in the ratio 1:7:19.