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In DeltaABC, if sin A sin B=(ab)/(c^(2)...

In `DeltaABC`, if sin A sin B`=(ab)/(c^(2))`, then the triangle is

A

equilateral

B

isosceles

C

right angled

D

obtuse angled

Text Solution

Verified by Experts

The correct Answer is:
C
Given ,`sinAsinB=(ab)/(c^(2))`
`rArrc^(2)=(ab)/(sinAsinB)=((a)/(sinA))((b)/(sinB))`
`rArrc^(2)=((c)/(sinC))^(2) " " [because(a)/(sinA)=(b)/(sinB)=(c)/(sinC)]`
`rArrsin^(2)C=1rArrC=90^(@)`
Hence , `DeltaABC` is a right angled triangle.
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