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[" According to the equation "],[C(6)H(6...

[" According to the equation "],[C_(6)H_(6(1))+(7)/(2)O_(2(x))rarr6CO_(2(x))+3H_(2)O_((1)),Delta H=-xKJ],[" The energy evolved when "3.9" gm of benzene "],[" is burnt in air is "-163.2KJ" heat of combustion "],[" of benzene is "],[[" 1) "32.46KJ," 2) "16.32KJ],[" (3) "326.4KJ," 4) "-3264KJ]],[" 3) "326.4KJ," 4) "-3264KJ]

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According to the equation C_(6)H_(6(l))+7/2 O_(2(g)) rarr 6CO_(2(g))+3H_(2)O_((l)), DeltaH=-xkJ The energy evolved when 3.9 gm of benzene is burnt in air is - 163.2 kJ heat of combustion of benzene is

According to equation, C_(6)H_(6)(l)+15//2 O_(2)(g)rarr 6CO_(2)(g)+3H_(2)O(l), Delta H= -3264.4 "KJ mol"^(-1) the energy evolved when 7.8 g benzene is burnt in air will be -

According to equation, C_(6)H_(6)(l)+15//2 O_(2)(g)rarr 6CO_(2)(g)+3H_(2)O(l), Delta H= -3264.4 "KJ mol"^(-1) the energy evolved when 7.8 g benzene is burnt in air will be -

According to the equation, C_6H_6(l)+15/2O_2(g)rarr3H_2O(l)+6C_2(g) triangleH =-3264.4kJ/mol, the energy evolved when 7.8 g of benzene is burnt in air will be:

According to the reaction C_(6)H_(6)+15//2O_(2)to3H_(2)O+6CO_(2) ( DeltaH=-3264.6 kJ // mol ) the energy evolved when 3.9g of benzene is burnt in air will be

How much heat is evolved if 3.2 g of methane is burnt and if the heat of combustion of methane is -880" kJ mol"^(-1) ?

How much heat is evolved if 3.2 g of methane is burnt and if the heat of combustion of methane is -880" kJ mol"^(-1) ?

The heat evolved in the combustion of benzene is given by. the equation: 'C_6 H_6(g)+(15)/2 O_2(g) rarr 6 CO_2^(g)+3 H_2 O(l), Delta H=-3264.6 kJ mol^(-1)' The heat energy change when '39 g' of 'C_6 H_6' are burnt in an open container will be: