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At the suggestion of Ernest Rutherford, ...

At the suggestion of Ernest Rutherford, Hans Geiger and Ernest Marsden bombarded a thin gold foil by d-particles from a polonium source. It was expected that O-particles would go right through the foil with hardly any deflection. Although most of the alpha particles indeed were not deviated by much, a few were scattered through very large angles. Some were even scattered in the backward direction. The only way to explain the results Rutherford found, was to picture an atom as being composed of a tiny nucleus in which it is positive charge and nearly all its mass is concentrated.
Rutherford's c-particle scattering experiment led to the conclusion that

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B
Main point of Rutherford.s nuclear model.
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In the gold foil experiment of Geiger and Marsden, that paved the way for Rutherford's model of an atom, `~ 1.00%` of the `alpha`-particles were found to deflect at angles `gt 50^(@)`. If one mole of `alpha`-particles were bombarded on the gold foil, compute the number of `alpha`-particles that would deflect at angles less than `50^(@)`.

At the suggestion of Earnest Rutherford, hans Geiger and ernest Marsden bombarded a thin gold foil by alpha -particles from a polonium source. It was expected that alpha -particles would go right through the foil with hardly any deflection. Although, most of the alpha particles indeed were not deviated by much, a few were scattered through veryi large angles. Some were even scattered in the backward direction. The nly way to explain the results, rutherford found, was to picture an atom as being compoed of a tiny nucleus in which its positive charge and nearly all its mass are concentrated. Scattering of alpha -particles is proportional to target thickness and is inversely proportional to the fourth power of sin((theta)/(2)) , where, theta is scattering angle. Distance of closest approach may be calculated as: r_("min")=(Z_(1)Z_(2)e^(2))/(4piepsi_(0)K) where, K=kinetic energy of alpha -particles. Q. Rutherford's alpha -particle scattering led to the conclusion that:

At the suggestion of Earnest Rutherford, hans Geiger and ernest Marsden bombarded a thin gold foil by alpha -particles from a polonium source. It was expected that alpha -particles would go right through the foil with hardly any deflection. Although, most of the alpha particles indeed were not deviated by much, a few were scattered through veryi large angles. Some were even scattered in the backward direction. The nly way to explain the results, rutherford found, was to picture an atom as being compoed of a tiny nucleus in which its positive charge and nearly all its mass are concentrated. Scattering of alpha -particles is proportional to target thickness and is inversely proportional to the fourth power of sin((theta)/(2)) , where, theta is scattering angle. Distance of closest approach may be calculated as: r_("min")=(Z_(1)Z_(2)e^(2))/(4piepsi_(0)K) where, K=kinetic energy of alpha -particles. Q. Rutherford's scattering formula fails for vary small scattering angles because:

At the suggestion of Earnest Rutherford, hans Geiger and ernest Marsden bombarded a thin gold foil by alpha -particles from a polonium source. It was expected that alpha -particles would go right through the foil with hardly any deflection. Although, most of the alpha particles indeed were not deviated by much, a few were scattered through veryi large angles. Some were even scattered in the backward direction. The nly way to explain the results, rutherford found, was to picture an atom as being compoed of a tiny nucleus in which its positive charge and nearly all its mass are concentrated. Scattering of alpha -particles is proportional to target thickness and is inversely proportional to the fourth power of sin((theta)/(2)) , where, theta is scattering angle. Distance of closest approach may be calculated as: r_("min")=(Z_(1)Z_(2)e^(2))/(4piepsi_(0)K) where, K=kinetic energy of alpha -particles. Q. Alpha particles that come closer to the nuclei:

At the suggestion of Earnest Rutherford, hans Geiger and ernest Marsden bombarded a thin gold foil by alpha -particles from a polonium source. It was expected that alpha -particles would go right through the foil with hardly any deflection. Although, most of the alpha particles indeed were not deviated by much, a few were scattered through veryi large angles. Some were even scattered in the backward direction. The nly way to explain the results, rutherford found, was to picture an atom as being compoed of a tiny nucleus in which its positive charge and nearly all its mass are concentrated. Scattering of alpha -particles is proportional to target thickness and is inversely proportional to the fourth power of sin((theta)/(2)) , where, theta is scattering angle. Distance of closest approach may be calculated as: r_("min")=(Z_(1)Z_(2)e^(2))/(4piepsi_(0)K) where, K=kinetic energy of alpha -particles. Q. Which of the following quantities will be zero for alpha particles at the point of closest approach to the gold atom, in Rutherford's scattering of alpha particles?

Which one did Rutherford consider to be supported by the results of experiments in which a-particles were scattered by gold foil?

In the study of Geiger-Marsden experiment on scattering of alpha particles by a thin foil of gold, draw the trajectory of alpha-particles in the coulomb field of target nucleus, Explain briefly how one gets the information on the size of the nucleus from this study.

Draw a schematic arrangement of Geiger-Marsden experiment showing the scattering of C-particles by a thin foil of gold. Why is it that most of the O-particles go right through the foil and only a small fraction gets scattered at large angles ?

गीगर और मार्सडेन के सोने की पन्नी वाले प्रयोग में, जिसने रदरफोर्ड के परमाणु मॉडल की राह दिखाई `~1.00%alpha`-कण `50^(@)` से अधिक कोणों पर विक्षेपित होते पाए गए। यदि सोने की पन्नी पर एक मोल `alpha`-कणों की बौछार की गई, तो `50^(@)` से कम के कोणों पर विक्षेपित हुए `alpha`-कणों की संख्या परिकलित कीजिए।

In the Rutherford’s experiment of alpha particles scattering on thin gold foil, in 1911, it was found that only ion `alpha`-particle among, 20,000 was deflected through `180^@`. This was due to

When the atoms of the gold foil are bombarded by a beam of a particles, only a few alpha -particles get deflected, whereas most of them go straight, undeflected. This is because

What conclusions are drawn from rutherford 's experiment on the scattering of alpha particles from a thin gold foil

At the suggestion of Ernest Rutherford, Hans Geiger and Ernest Marsden bombarded a thin gold foil by d-particles from a polonium source. It was expected that O-particles would go right through the foil with hardly any deflection. Although most of the alpha particles indeed were not deviated by much, a few were scattered through very large angles. Some were even scattered in the backward direction. The only way to explain the results Rutherford found, was to picture an atom as being composed of a tiny nucleus in which it is positive charge and nearly all its mass is concentrated.
The C-particle scattering experiment led to the conclusion that

At the suggestion of Ernest Rutherford, Hans Geiger and Ernest Marsden bombarded a thin gold foil by d-particles from a polonium source. It was expected that O-particles would go right through the foil with hardly any deflection. Although most of the alpha particles indeed were not deviated by much, a few were scattered through very large angles. Some were even scattered in the backward direction. The only way to explain the results Rutherford found, was to picture an atom as being composed of a tiny nucleus in which it is positive charge and nearly all its mass is concentrated. Which of the following is not correct observation/ conclusion from Rutherford's scattering experiment?

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