A particle of mass (m) is attached to a spring (of spring constant k) and has a narural angular frequency omega_(0). An external force `R(t)` proportional to cos omegat(omega!=omega)(0) is applied to the oscillator. The time displacement of the oscillator will be proprtional to.

Options

A. (a) `1/(m(omega_(0)^(2)+omega^(2))`
B. (b) `1/(omega(omega_(0)^(2)-omega^(2))`
C. (c ) `m/(omega_(0)^(2)-omega^(2)`
D. (d) `m/(om_(0)^(2)+omega^(2))`

Answer

B

Explanation

(b) Equation of desplacement is given by `x=A sin(omegat+phi)
where `A=f_(0)/(m(omega_(0)^(2)-omega^(2)))`.