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Find the wave number of a photon having ...

Find the wave number of a photon having an energy of 2.072 eV.
Given :
Charge on electron `=1.6xx10^(-19)C`
Velocity of light air `=3xx10^(8)" m"//"s"`
Planck's constant `=6.63xx10^(-34)" J-s"`.

Text Solution

AI Generated Solution

To find the wave number of a photon with an energy of 2.072 eV, we will follow these steps: ### Step 1: Convert Energy from eV to Joules The energy of the photon is given in electron volts (eV). We need to convert this energy into joules (J) using the conversion factor: \[ 1 \text{ eV} = 1.6 \times 10^{-19} \text{ J} \] So, the energy in joules is: \[ ...
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Give the order of the following : Planck's constant ( 6.63xx10^(-34) J-s)

What is the work fimetion (in eV) of the metal if the light of wavelength 4000A generates photoelectrons of velocity 6 xx 10^(5) ms^(-1) from it? (Mass of electron= 9 xx 10^(-31) kg, Velocity of light = 3 xx 10^(8) ms^(-1) Planck’s constant= 6.626 xx 10^(-34) Js, Charge of electron = 1.6 xx 10^(19) JeV^(-1)

Knowledge Check

  • what is the work fuction of the metal if the light of wavelength 4000Å generates photoelectrons of velocity 6xx10^(5) ms^(-1) from it ? (Mass o felectron =9xx10^(-31) kg Velocity of light =3xx10^(8)ms^(-1) Planck's constant =6.626xx10^(-34)Js Charge of electron =1.6xx10^(-19)jeV^(-1)

    A
    `0.9eV`
    B
    `3.1eV`
    C
    `2.1eV`
    D
    `2.1eV`
  • What is the approximate value of the de broglie wavelength of an electron having 80 eV of electron ? (1eV = 1.6xx10^(-19) J " mass of electron " = 9xx10^(-31) kg, " Plank's constant " = 6.6xx10^(-34) J-sec)

    A
    14 Å
    B
    1.4 Å
    C
    140 Å
    D
    0.14 Å
  • The de - Broglie wavelength of an electron having 80 ev of energy is nearly ( 1eV = 1.6 xx 10^(-19) J , Mass of electron = 9 xx 10^(-31) kg Plank's constant = 6.6 xx 10^(-34) J - sec )

    A
    `140 Å`
    B
    `0.14 Å`
    C
    `14 Å`
    D
    `1.4 Å`
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