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Use product `[[1,-1, 2],[ 0, 2,-3],[ 3,-2, 4]] [[-2, 0, 1],[ 9, 2,-3],[ 6, 1,-2]]` to solve the system of equation: `x-y+2z=1`; `2y-3z=1`; `3x-2y+4z=2`

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To solve the system of equations using the product of the given matrices, we will follow these steps: ### Step 1: Define the Matrices We have two matrices: - Matrix A: \[ A = \begin{bmatrix} 1 & -1 & 2 \\ ...
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The solution of the system of equations is x-y+2z=1,2y-3z=1 and 3x-2y+4y=2 is

Use product [{:(1,-1,2),(0,2,-3),(3,-2,4):}][{:(-2,0,1),(9,2,-3),(6,1,-2):}] to solve the equations : x-3z=9 , -x+2y-2z=4 , 2x-3y+4z=-3

Determine the product [[-4, 4, 4], [-7, 1, 3],[5, -3, -1]][[1, -1, 1],[1, -2, -2],[2, 1, 3]] and use it to solve the system of equations x – y + z = 4, x – 2y – 2z = 9, 2x + y + 3z = 1

Use product [[1,-1,20,2,-33,-2,4]][[-2,0,19,2,-36,1,-2]] system of equations x-y+2z=12y-3z=13x-2y+4z=2

Solve the system of equations by cramer's rule: 2x-3y+z=-1 ,3x+y-2z=1 and 4x-y+z=9

Given A=[[1,-1, 0], [2, 3, 4], [0, 1, 2]], B= [[2,2,-4],[-4,2,-4],[2,-1,5]] find AB and use this to solve the system of equations: y+2x=7,x-y=3,2x+3y+4z=17

If A=[[2,3,4],[1,-1,0],[0,1,2]] , find A^(-1) . Hence, solve the system of equations x-y=3, 2x+3y+4z=17, y+2z=7

Determination the product [{:(,1,-1,1),(,1,-2,-2),(,2,1,3):}] [{:(,-4,4,4),(,-7,1,3),(,5,-3,-1):}] and use it to solve the system of equations x-y+z=4, x-2y-2z=9, 2x+y+3z=1

The equations x+2y+3z=1 2x+y+3z=1 5x+5y+9z=4

If matrix A=[[2,1,-3],[3,2,1],[1,2,-1]] . Find A^(-1) and hence solve the system of equation 2x+y–3z=13, 3x+2y+z=4, x+2y-z=8

XII BOARDS PREVIOUS YEAR-BOARD PAPER SOLUTIONS-All Questions
  1. Using elementary transformations, find the inverse of the matrix : [...

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  2. If vec a= hat a= hat i-\ hat j+7 hat k and vec b=5 hat j-\ hat j+l...

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  3. Use product [[1,-1, 2],[ 0, 2,-3],[ 3,-2, 4]] [[-2, 0, 1],[ 9, 2,-3],[...

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