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A particle moves in the plane xy with co...

A particle moves in the plane xy with constant acceleration 'a' directed along the negative y-axis. The equation of motion of the particle has the form `y= px - qx^2` where p and q are positive constants. Find the velocity of the particle at the origin of co-ordinates.

Text Solution

Verified by Experts

The correct Answer is:
A
Comparing the given equation with the equation of a projectile motion,
`y= x tan theta - (gx^2)/(2u^2)(1+ tan^2 theta)`
We find that `g= a, tan theta = p and a/(2u^2) (1+tan^2 theta) = q`
`:. u=` velocity of particle at origin
` = sqrt((a(1+tan^2theta))/(2q)) = sqrt((a(1+p^2))/(2q))` .
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Knowledge Check

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