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In a conical pendulum arrangement, a str...

In a conical pendulum arrangement, a string of length 1 m is fixed at one end with a bob of mass `100 g` and the string makes `4 rad per sec` around a vertical axis through a fixed point. The angle of inclination of the string with vertical is: (Take `g = 10 ms^(-1)`)

A

`tan^(-1)((5)/(8))`

B

`tan^(-1)((3)/(5))`

C

`cos^(-1)((3)/(5))`

D

`cos^(-1)((5)/(8))`

Text Solution

Verified by Experts

The correct Answer is:
D
`Tcostheta=mg` ...(i)
`Tsintheta=mromega^(2)=m(lsintheta)omega^(2)` ...(ii)

Solving these two equation we get,
. `costheta=(g)/(lomega^(2))=(g)/(l(2pin)^(2))`
`=(10)/([2pixx(2)/(pi)]^(2))` , `(l=1m)`
`theta=cos^(-1)(5//8)`
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Knowledge Check

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