A heavy ball moving with speed `v` collides with a tiny ball. The collision is elastic, then immediately after the impact, the second ball will move with a speed approximately equal to

Options

A. (a) `v`
B. (b) `2v`
C. (c) `v/2`
D. (d) `v/3`

Answer

B

Explanation

`m_1 gt gt m_2`
`v_2^()'=((m_2-m_1)/(m_1+m_2))v_1+((2m_1)/(m_1+m_2))v_2`
Substituting `m_2=0` and `v_1=0` we get,
`v_2=2v`