A uniform electric field of 400 V/m is d...

A uniform electric field of `400 V/m` is directed at `45^@` above the x-axis as shown in the figure. The potential difference `V_A-V_B` is given by

`4V`

`6.4V`

`2.8V`

Text Solution

Verified by Experts

The correct Answer is:

`E=400 cos45^@hati+400sin45^@hatj`
`V_A-V_B=-int_B^AE.dr`
where `dr=dxhati+dyhatj`

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