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A deuteron (the nucleus of an isotope of...

A deuteron (the nucleus of an isotope of hydrogen) has a mass of `3.34 xx 10^-27` kg and a charge of `+e`. The deuteron travels in a circular path with a radius of `6.96 mm` in a magnetic field with magnitude `2.50 T`.
(a) Find the speed of the deuteron.
(b) Find the time required for it to make half of a revolution.
(c) Through what potential difference would the deuteron have to be accelerated to acquire this speed?

Text Solution

Verified by Experts

The correct Answer is:
B
a. `r=(mv)/(Bq)impliesv=(Bqr)/m`
b. `t=T/2=(pim)/(Bq)`
c. `r=sqrt((2qVm))/(Bq)`
`:. V=(r^2B^2q^2)/(2qm) =(r^2B^2q)/(2m)`
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  • An electron having mass (9.1 xx 10^(-31) kg) and charge (1.6 xx 10^(-19)C) moves in a circular path of radius 0.5 m with a velocity 10^(6) m"/"s in a magnetic field. Strength of magnetic field is

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