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The ratio of the intensity at the centre...

The ratio of the intensity at the centre of a bright fringe to the intensity at a point one quarter of the fringe width from the centre is

A

1

B

`1/2`

C

`3/4`

D

`1/4`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the ratio of the intensity at the center of a bright fringe to the intensity at a point one quarter of the fringe width from the center. ### Step-by-Step Solution: 1. **Understanding the Fringe Width**: The fringe width (w) is the distance between two consecutive bright or dark fringes in an interference pattern. The center of the pattern corresponds to the central maximum. 2. **Intensity at the Center**: At the center of the bright fringe (central maximum), the intensity is maximum. We denote this intensity as \( I_{\text{max}} \). 3. **Finding the Position of Interest**: We need to find the intensity at a point that is one quarter of the fringe width from the center. This position can be expressed as: \[ x = \frac{w}{4} \] 4. **Intensity Formula in Interference**: The intensity at a point in an interference pattern can be expressed as: \[ I = I_{\text{max}} \cos^2\left(\frac{\pi x}{w}\right) \] where \( I_{\text{max}} \) is the maximum intensity, and \( x \) is the distance from the center. 5. **Calculating Intensity at \( x = \frac{w}{4} \)**: Substitute \( x = \frac{w}{4} \) into the intensity formula: \[ I\left(\frac{w}{4}\right) = I_{\text{max}} \cos^2\left(\frac{\pi \left(\frac{w}{4}\right)}{w}\right) \] Simplifying this gives: \[ I\left(\frac{w}{4}\right) = I_{\text{max}} \cos^2\left(\frac{\pi}{4}\right) \] Since \( \cos\left(\frac{\pi}{4}\right) = \frac{1}{\sqrt{2}} \): \[ I\left(\frac{w}{4}\right) = I_{\text{max}} \left(\frac{1}{\sqrt{2}}\right)^2 = I_{\text{max}} \cdot \frac{1}{2} \] 6. **Finding the Ratio of Intensities**: Now we need to find the ratio of the intensity at the center to the intensity at \( \frac{w}{4} \): \[ \text{Ratio} = \frac{I_{\text{max}}}{I\left(\frac{w}{4}\right)} = \frac{I_{\text{max}}}{\frac{I_{\text{max}}}{2}} = 2 \] ### Final Answer: The ratio of the intensity at the center of a bright fringe to the intensity at a point one quarter of the fringe width from the center is **2**.

To solve the problem, we need to find the ratio of the intensity at the center of a bright fringe to the intensity at a point one quarter of the fringe width from the center. ### Step-by-Step Solution: 1. **Understanding the Fringe Width**: The fringe width (w) is the distance between two consecutive bright or dark fringes in an interference pattern. The center of the pattern corresponds to the central maximum. 2. **Intensity at the Center**: ...
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