Home
Class 12
PHYSICS
The electirc potential between a proton ...

The electirc potential between a proton and an electron is given by `V = V_0 in (r )/(r_0)` , where r_0 is a constant. Assuming Bhor model to be applicable, write variation of `r_n` with n, being the principal quantum number. (a) `r_n prop n` (b) `r_n prop (1)/(n)` (c ) `r_n^2` (d)`r_n prop (1)/(n^2)`

Text Solution

Verified by Experts

`:. U = eV = eV_0 in ((r )/(r_0))`
`|F| = |-(dU)/(dr)| = (eV_0)(r )`
This force will provide the necessary centripetal force. Hence, `(mv^2)/(r ) = (eV_0)/(r )`
or `v= sqrt(eV_0)/(m)
.....(i) Moreover, ` mur = (nh)/(2pi)
....(ii) Dividing Eq. (ii) by Eq. (i) we have
`mr = ((nh)/(2pi)) sqrt(m)/(eV_0) or r_n prop n`
Promotional Banner

Topper's Solved these Questions

  • MODERN PHYSICS - 1

    DC PANDEY|Exercise Example Type 3|4 Videos

  • MODERN PHYSICS - 1

    DC PANDEY|Exercise Example Type 4|3 Videos

  • MODERN PHYSICS - 1

    DC PANDEY|Exercise Example Type 1|2 Videos

  • MODERN PHYSICS

    DC PANDEY|Exercise Integer Type Questions|17 Videos

  • MODERN PHYSICS - 2

    DC PANDEY|Exercise Level 2 Subjective|10 Videos

Similar Questions

Explore conceptually related problems

The elecrric potential between a proton and as electron is given by V= V_(0) ln (r /r_(0)) , where r_(0) is a constant . Assuming Bohr's model to be applicable , write variation of r_(n) with n , n being the principal quantum number ?

The potential of an atom is given by V=V_(0)log_(e)(r//r_(0)) where r_(0) is a constant and r is the radius of the orbit Assumming Bohr's model to be applicable, which variation of r_(n) with n is possible (n being proncipal quantum number)?

The sum of series Sigma_(r=0)^(r) (-1)^r(n+2r)^2 (where n is even) is

If n is an even natural number , then sum_(r=0)^(n) (( -1)^(r))/(""^(n)C_(r)) equals

Given that C(n, r) : C(n,r + 1) = 1 : 2 and C(n,r + 1) : C(n,r + 2) = 2 : 3 . What is P(n, r) : C(n, r) equal to ?

If a_(n)=sum((1)/(C)(n,r) from r=0 to n, then sum((r)/(C)(n,r))

The sum of the series sum_(r=0)^(n)(-1)^(r)(n+2r)^(2) (where n is even) is equal to