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The velocity with which a projectile mus...

The velocity with which a projectile must be fired so that is escapes earth's gravitation does not depend on:

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The correct Answer is:
B
For a projectile to leave the gravitational field of the earth, its kinetic energy would be at least equal to potential energy. That is
`1/2mv_e^2=G(Mm)/(R) rArr v_e= sqrt((2GM)/(R))`
Where G is the universal gravitational constant, M is the mass of the earth and R is the radius of the earth. hence the escape velocity of a projectile is independent of its own mass
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