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For sky wave propagation of a 10 MHz sig...

For sky wave propagation of a `10 MHz` signal, what should be the minimum electron density in ionosphere?

A

`~1.2xx10^(12)m^(-3)`

B

`~10^(6)m^(-1)`

C

`~10^(14)m^(-3)`

D

`~10^(22) m^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
A
The critical frequency of a sky wave for reflection from a layer of atmosphere is given by `f_(c)=9(N_("max"))^(1//2)`
where N is the density of electron `"/"M^(3)`.
`10xx10^(6)=9(N_("max"))^(1//2)`
`N_("max")=((10xx10^(6))/(9))^(2)cong 1.2xx10^(12) m^(-3)`.
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Knowledge Check

  • For sky wave propagation of 10 MHz signal, what should be the minimum electron density in ionosphere?

    A
    `~10^(14)m^(-3)`
    B
    `~10^(6)m^(-3)`
    C
    `~1.2^(12)m^(-3)`
    D
    `~10^(22)m^(-3)`

  • If the critical frequency for sky wave propagation is 12 MHz , then the maximum electron density in the ionosphere is

    A
    ` 1.78 xx 10^(12) m^(-3) `
    B
    ` 0.178 xx 10^(10) m^(-3)`
    C
    ` 1.12 xx 10^(12) m^(-3)`
    D
    `0.56 xx 10^(12) m^(-3)`

  • Sky wave propagation is also called

    A
    tropospheric wave propagation
    B
    satellite communication
    C
    ionospheric wave propagation
    D
    none of these

    • Similar Questions

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    For sky wave propagation of a 10 MHz signal, which of the following statements are true:

    Describe sky wave propagation in brief.

    On a particular day, the maximum frequency reflected from the ionosphere is 12 MHz, On another day, it was found to decrease to 9 MHz. By what percentage the maximum electron density of the ionosphere has been decreased.

    On a particular day, the maximum frequency reflected from the ionosphere is 9 MHz. On another day. It was found to increase by 1 MHz. Calculate the rate of the maximum electron densities of the ionosphere on the two days

    On a particular day, the maximum frequency reflected from the ionosphere is 10MHz. After 10 days, it increaesed to 11 MHz. What is the ratio of the maximum electron density of the ionosphere on these two days ?

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