Home
Class 12
PHYSICS
A convex lens of refractive index 3/2 ha...

A convex lens of refractive index 3/2 has a power of `2.5^(@)`. If it is placed in a liqud of refractive index 2,the new power of the lens is

Doubtnut Promotions Banner Mobile Dark

Text Solution

Verified by Experts

The correct Answer is:
A
Focal length of a convex lens having power
`2.5D,=(1)/(2.5)m`
Also focal length of a lens in a medium of refractive index `mu` is given by
`(1)/(f)=(mu-1)((1)/(R_(1))-(1)/(R_(2)))`
`rArr 2.5=(1)/(f)=((3)/(2)-1)((1)/(R_(1))-(1)/(R_(2)))" ...(i) (in air)"`
`rArr (1)/(f')=((3)/(4)-1)((1)/(R_(1))-(1)/(R_(2)))" ...(ii) "[because .^(t)mu_(s)=(3)/(4)]" in liquid" `
Dividing the two, `2.5f'=(0.5)/(-0.25)`
`rArr" "(1)/(f')=(-5)/(25xx0.25)=-1.25D`
|

Topper's Solved these Questions

  • AIIMS 2008

    AIIMS PREVIOUS YEAR PAPERS|Exercise PHYSICS|60 Videos

  • AIIMS 2010

    AIIMS PREVIOUS YEAR PAPERS|Exercise PHYSICS|60 Videos

Similar Questions

Explore conceptually related problems

A convex lens of refractive index 3/2 has a power of `2.5^(@)`. If it is placed in a liqud of refractive index 2,the new power of the lens is

When a lens of power P (in air) made of material of refractive index mu is immersed in liquid of refractive index mu_(0) Then the power of lens is:

उत्तल लेंस को लेंस के पदार्थ के अपवर्तनांक से कम अपवर्तनांक वाले द्रव में डुबाने पर उत्तल लेंस व्यवहार करेगा-

The focal length of a glass convex lens of refractive index 1.5 is 20 cm. What is the focal power of the lens when immersed in a liquid of refractive index of 1.25 ?

एक उत्तल लेंस एक ऐसे माध्यम में रखा जाता है, जिसका अपवर्तनांक लेंस के अपवर्तनांक के बराबर है| इस माध्यम में लेंस की फोकस दुरी क्या होगी?

A double convex lens of refractive index m_(1) is immersed in a liquid of refractive index m_(2) . This lens will act as:

A convex lens has a focal length of 0.1 m in air. Calculate its power. If the lens is completely dipped in `CS_(2)` of refractive index 1.66, then what will be the change in power of the lens? Given R.I of the convex lens = 1.50.

If a convex lens is dipped in a liquid whose refractive index is equal to the refractive index of the lens, then lens acts like a

The refractive index of a convex lens material is 1.46. Imagine how the lens behaves when the upper lens, which has a refractive index of benzene 1.5 and a water refractive index of 1, is placed in water and benzene.

1.5 अपवर्तनांक वाले उत्तल लेंस को उतने ही अपवर्तनांक वाले तरल में रखा जाता है। इस माध्यम में लेंस की फोकस दूरी क्या होगी?

A convex lens has a refractive index 1.5 and power 7 diopter. When the lens is immersed in a liquid, it behaves as a concave lens of focal length 120 cm. Calculate the refractive index of the liquid.

Power of a convex lens of refractive index `3/2` is 2.5 D in air. If it is inerted in liquid of refractive index 2, then new power will be ......

A convex lens of refractive index 3/2 has a power of 2.5^(@) . If it is placed in a liqud of refractive index 2,the new power of the lens is

A thin convex lens of crown glass having refractive index 1.5 has power 1 D. What will be the power of similar convex lens of refractive index 1.6 ?

A convex lens of refractive index `n` behaves as a convex lens of smaller power in a liquid of refractive index `n_1` and as a concave lens in another liquid of refractive index `n_2`. Then relation between `n, n_1` and `n_2` is

The radius of curvature of convex surface of a piano convex is.15 cm and refractive index of the lens is 1.6. The power of the lens is—

Home
Profile