If `a, b, c` are real and `a!=b`, then the roots ofthe equation, `2(a-b)x^2-11(a + b + c) x-3(a-b) = 0` are :

Options

A. real and equation
B. real and unequal
C. purely imaginary
D. none of these

Answer

B

Explanation

We have
`2(a-b)x^(2)-11(a+b+c)x-3(a-b)=0`
`:.D={-11(a+b+c)}^(2)-4.29a-b).(-3)(a-b)`
`=121(a+b+c)^(2)+24(a-b)^(2)gt0`
Therefore the roots are real and unequal.