The oxidation state of `Fe` in `Fe(CO)_(5)` is

Options

A. `0`
B. `+2`
C. `-2`
D. `+6`

Explanation

To determine the oxidation state of iron (Fe) in the compound Fe(CO)₅, we can follow these steps:

### Step 1: Identify the components of the compound
Fe(CO)₅ consists of one iron (Fe) atom and five carbon monoxide (CO) molecules.

### Step 2: Determine the oxidation state of CO
Carbon monoxide (CO) is a neutral molecule, meaning it has no charge. Therefore, the oxidation state of CO is 0.

### Step 3: Set up the equation for the oxidation state
Let the oxidation state of iron (Fe) be represented as \( X \). Since the compound Fe(CO)₅ is neutral, the sum of the oxidation states of all the atoms in the compound must equal 0.

### Step 4: Write the equation
The equation can be set up as follows:
\[ X + (5 \times 0) = 0 \]

### Step 5: Solve for X
This simplifies to:
\[ X + 0 = 0 \]
\[ X = 0 \]

### Conclusion
The oxidation state of iron (Fe) in Fe(CO)₅ is 0.

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