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Assuming ideal behaviour, calculate Boyl...

Assuming ideal behaviour, calculate Boyle's law constant for each of the following gase at `25^(@)C`
a. 10g of `O_(2)` in 2 L container
b. 8g of `CH_(4)` in 5 L container

Text Solution

Verified by Experts

Boyle's law constant is given by product of PV at a given temperature.
Now. PV=nRT
a. 10g of `O_(2)=10//32` mol
Thus, PV`=(10xx0.0831xx298.15)/(32)=7.74`L bar
(b). 18g of `CH_(4)=8//16=0.5` mol
thus `PV=0.5xx0.0831xx298.15=12.38` L bar
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Knowledge Check

  • Molar concentration of 96 g of O_(2) (in mol L^(-1) ) contained in 2-L vessel is

    A
    16
    B
    1.5
    C
    4
    D
    24

  • Molar concentration of 96 g of O_(2) contained in a 2 L vessel is:

    A
    `16 mol//L`
    B
    `1.5 mol//L`
    C
    `4 mol//L`
    D
    `24 mol//L`

  • Nitric oxide (NO) reacts with molecular oxygen as follows: 2NO(g)+O_(2)(g) rarr 2NO_(2)(g) Initially NO and O_(2) are separated as shown below. When the valve is opened the reaction quickly goes to completion Assume that the temperature remains constant at 27^(@) C [ R=0.08 atm lit//mol//K] The ratio of partial pressure of NO_(2) in 4L container to 2L container is:

    A
    1
    B
    2
    C
    3
    D
    `0.5`
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