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In the van der Waals equation (P + (n^...

In the van der Waals equation
`(P + (n^(2)a)/(V^(2)))(V - nb) = nRT`
the constant a reflects the actual volume of the gas molecules.

Answer

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The van der Waal equation of gas is (P + (n^(2)a)/(V^(2))) (V - nb) = nRT

In the Van der Waals equation (P + (n^(2)a)/(V^(2))) (V-nb) = nRT , why is the term n^(2)a//V^(2) positive in sign.

Knowledge Check

  • [P+(an^(2))/(V^(2))](V-nb) = nRT is -

    A
    Vander waals equation
    B
    Combined gas law
    C
    Boyle's Law
    D
    None of these

  • Units of a and b in van der Waal's equation (P+(an^(2))/(V^(2)))(V-nb)=nRT are

    A
    `L^(2)atm^(-1), L`
    B
    `atm L^(-2), L^(-1)`
    C
    `L^(2) atm^(-1) mol^(-2), L mol^(-1)`
    D
    `atm L^(2)mol^(-2), L mol^(-1)`

  • The van der Waals equation for 1 mole of gas is (p+a/V^(2))(V-b)=RT where,

    A
    p and V are ideal pressure and ideal volume respectively
    B
    (V - b) is the real volume
    C
    `(p+a/V^(2))` is the ideal pressure
    D
    `(p+a/V^(2))` is the real pressure

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    In the Van-der-Waals equation (p_(1)+(a)/(v^(2)))(v-b) =RT.Find the dimension of a and b

    Write van der Waal equation for n mol of gas.

    Deviation of real gases from ideal behaviour can be studied by plots of compressibility factor (Z) vs p. The copressibility factor is Z=(pV)/(nRT) The compressibility factor for 1 mole of a gas obeying van der Waals gas equation at 0^(@)C and 100 atm pressure is found to be 0.5. The van der Waals gas equation is (p(an^(2))/(V^(2)))(V-nb)=nRT Calculate the value of 'a' assuming volume of molecules to be negligible.

    The unit of the van der Waals gas equation parameter 'a' in (P+(an^(2))/(V^(2)))(V-nb)=nRT is :

    The van der Waals' equation for a real gas is:

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