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Calculate the change in entropy for the fusion of `1 mol` of ice. The melting point of ice is `300K` and molar enthalpy of fustion for ice `= 6.0 k J mol^(-1)`.

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For entropy change of fustion, `Delta_(f)S^(Theta) = (Delta_(f)H^(Theta))/(T)`
Given, `Delta_(f)H^(Theta) = 6 xx 10^(3) J, T = 300 K`
`:. Delta_(f)S^(Theta) = (6 xx 10^(3))/(300) = 20.0 J K^(-1) mol^(-1)`
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