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Calculated the Gibbs energy change on di...

Calculated the Gibbs energy change on dissolving one mole of sodium chloride at `25^(@)C`.
Lattice `=+ 777.0 kJ mol^(-1)`
Hydration of `NaCI =- 774.0 kJ mol^(-1)`
`DeltaS` at `25^(@)C = 40 J K^(-1) mol^(-1)`

Text Solution

Verified by Experts

`DeltaH =` Lattice energy - Hydration enegry
`=777 - 774 = 3kJ mol^(-1)`
`DeltaG = DeltaH - T DeltaS = 3 - 298 (40 xx 10^(-3))`
`=- 392 kJ mol^(-1)`
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