Home
Class 11
CHEMISTRY
When 1mol of a monoatomic ideal gas at T...

When `1mol` of a monoatomic ideal gas at `TK` undergoes adiabatic change under a constant external pressure of `1atm`, changes volume from `1 L to 2L`. The final temperature (in K) would be

A

`(T)/(2^(2//3))`

B

`T +(2)/(3xx0.0821)`

C

`T`

D

`T -(2)/(3 xx 0.0821)`

Text Solution

Verified by Experts

The correct Answer is:
D
Process `DeltaH = 0`
`DeltaE = DeltaW` ltbr. `DeltaW =- P DeltaV =- 1`
`DeltaE = nC_(V)DeltaT`
`C_(V) = (R )/(gamma-1), gamma=(5)/(3)` for monatomic sas
`(gamma=(C_(P))/(C_(V)))`
`C_(V) = (R )/((5)/(3)-1) =(3R)/(2)`
`n = 1`
`DeltaE = 1 xx (3R)/(2) xx (T_(2)-T) =- 1`
`T_(2) = T -(2)/(3 xx 0.0821)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THERMODYNAMICS

    CENGAGE CHEMISTRY|Exercise Archives (Assertion-Reasoning)|3 Videos

  • THERMODYNAMICS

    CENGAGE CHEMISTRY|Exercise Archives (Interger)|1 Videos

  • THERMODYNAMICS

    CENGAGE CHEMISTRY|Exercise Archives (Multiple Correct)|3 Videos

  • STOICHIOMETRY

    CENGAGE CHEMISTRY|Exercise Archives Subjective|33 Videos

Similar Questions

Explore conceptually related problems

1 mole of monoatomic ideal gas subjected to irreversible adiabatic expansion against constant external pressure of 1 atm starting from initial pressure of 5 atm and initial temperature of 300K till the final pressure is 2 atm. What is the final temperature (in K) in the process? (take R = 2 cal/mol K).

One mole of monoatomic ideal gas at T(K) is exapanded from 1L to 2L adiabatically under constant external pressure of 1 atm . The final tempreture of gas in kelvin is

Knowledge Check

  • When one mole of monoatomic ideal gas at T K undergoes adiabatic change under a constant external pressure of 1 atm changes volume from 1 litre to 2 litre. The final temperature in Kelvin would be

    A
    `(T)/(2^((2//3)))`
    B
    `T+(2)/(3xx0.0821)`
    C
    T
    D
    `T-(2)/(3xx0.0821)`

  • When one mole of monoatomic ideal gas at T temperature undergoes adiabatic change under a constant external pressure of 1 atm, change in volume is from 1 L to 2L. The final temperature in kelvin would be

    A
    `(T)/(2^((2//3)))`
    B
    `T+(2)/(3xx0.0821)`
    C
    `T`
    D
    `T-(2)/(3xx0.0821)`

  • When one mole of monoatomic ideal gas at T K undergoes adiabatic change under a constant external pressure of I atm and volume changes from 1 litre to 2 litre. The final temperature in Kelvin would be

    A
    `T/(2^((2//3)))`
    B
    `T+2/3xx0.0821`
    C
    T
    D
    `T-2/3xx0.0821`

    • Similar Questions

    Explore conceptually related problems

    One mole of an ideal monoatomic gas at 27^(@) C expands adiabatically against constant external pressure of 1 atm from volume of 10 dm^(3) to a volume of 20 dm^(3) .

    For a monoatomic ideal gas undergoing an adiabatic change, the relation between temperature and volume TV^(x) = constant, where x is

    One mole of an ideal monoatomic gas at temperature T and volume 1L expands to 2L against a constant external pressure of one atm under adiabatic conditions, then final temperature of gas will be:

    For a monoatomic ideal gas undergoing an adiabatic change, the relation between temperature and volume is TV^(x) = constant, where x is

    One mole of an ideal monoatomic gas at temperature T and volume 1 L expands to 2 L against a constant external pressure of one atm under adibatic conditions, then final temperature of gas will be :

    Home
    Profile