Home
Class 11
CHEMISTRY
What happens when an inert gas is added ...

What happens when an inert gas is added to
i. `PCl_(5)(g) hArr PCl_(3)(g) +Cl_(2)(g)`
ii. `2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g)`
at equilibrium at : (a) constant pressure and temperature and temperature, and (b) at constant volume and temperature.

Text Solution

Verified by Experts

Let us discuss what happens when inert gas is added to the following reaction at equilibrium stage:
`mA(g)+nB(g) hArr pC(g)+qD(g)`
If the reaction is at equilibrium, we have
`K_(eq)=Q` …(i)
Any factor (e.g change in the concentration of reactants`//` products or both) can have imapact (in terms of change in the concentration of reatants`//` products) on that reaction at equilibrium only if that factor changes the equation (i) so that `K_(eq) ne 0`
Two cases occur:
a. Inert gas addition at constant pressure:
`K_(eq)=Q=(p_(C)^(p) p_(D)^(q))/(p_(A)^(m) p_(B)^(n))` (at equilibrium)
and particle pressure `(p)=chiP_("Total")`
`["where" chi=n/n_("Total")="mole fraction"]`
Thus, when an inert gas is added, `chi` of each of the gas decreases and since `P_("Total")` is constant, the partial pressure decreases leading to a new equation:
`Q gt K_(eq)` or `Q lt K_(eq)`
which will depend on whether
`Deltan_(g)=Singma(n_(g))_(P)-Sigma(n_(g))_(R) lt 0 "or" gt 0`, respectively.
`rArr PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g)`
`Deltan_(g)=1 gt 0 rArr Q lt K_(eq)`
(Reaction will move in forward direction)
Similarly, `2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g)`
`Deltan_(g)=-1 lt 0 rArr Q gt K_(eq)`
(Reaction will move in the backward direction)
b. Inert gas addition at constant volume:
`K_(eq)=Q=(p_(C)^(p) p_(D)^(q))/(p_(A)^(m) p_(B)^(n))` (at equilibrium)
and particle pressure `(p)=chiP_("Total")`
`["where" chi=n/n_("Total")="mole fraction"]`
Now, when inert gas is added at constant volume, `P_("Total") uarr` and `chi darr` but partial pressure of each gas remains same, since:
Partial pressure `(p)=n/n_("Total").P_("Total")` and using Dalton's Law and ideal gas equation:
`P_("Total").V=n_("Total")RT["check":P_("Total")/n_("Total")=(RT)/(V)="constant"]`
Thus, `K_(eq)=Q` even on adding inert gas at constant volume. Thus, adding inert gas at constant volume has no effect on a reaction at equilibrium.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Concept Applicationexercise 7.1|53 Videos
  • CHEMICAL EQUILIBRIUM

    CENGAGE CHEMISTRY|Exercise Ex 7.2|40 Videos
  • CHEMICAL BONDING AND MOLECULAR STRUCTURE

    CENGAGE CHEMISTRY|Exercise Archives Subjective|15 Videos
  • CLASSIFICATION AND NOMENCLATURE OF ORGANIC COMPOUNDS

    CENGAGE CHEMISTRY|Exercise Analytical and Descriptive Type|3 Videos

Similar Questions

Explore conceptually related problems

What happence to the equilibrium PCl_(5) (g) hArr PCl_(3) (g) + Cl_(2) (g), if nitrogen gas is added to it (i)at constant volume(ii) at constant pressure ? Give reasons.

For the reaction : 2SO_(2)(g)+O_(2)(g) hArr2SO_(3)(g),DeltaH=ve . An increase in temperature shows:

Knowledge Check

  • For the reaction, PCl_(5)(g)to PCl_(3)(g)+Cl_(2)(g)

    A
    `DeltaH=DeltaE`
    B
    `DeltaH gt DeltaE`
    C
    `DeltaH lt DeltaE`
    D
    none of these
  • Consider the reactions (i) PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) (ii) N_(2)O_(4) (g) hArr 2NO_(2)(g) The addition of an inert gas at constant volume

    A
    will increase the dissociation of `PCl_(5)` as well `N_(2) O_(4)`
    B
    will reduce the dissociation of `PCl_(5)` as well as `N_(2)O_(4)`
    C
    will increase the dissociation of `PCl_(5)` and step up the formation of `NO_(2)`
    D
    will not disturb the equilibrium of the reactions.
  • Consider the reactions (i) PCI_(5)(g)hArrPCI_(3)(g)+CI_(2)(g) (ii) N_(2)O_(4)(g)hArr2NO_(2)(g) The addition of an inert gas at constant volume

    A
    will increase the dissociation of `PCl_(5)` as well as `N_(2)O_(4)`
    B
    will reduce the dissociation of `PCl_(5)` aswell as `N_(2)O_(4)`
    C
    will increase the dissociation of `PCl_(5)` and step up the formation of `NO_(2)`
    D
    will not disturb the equilibrium of the reactions
  • Similar Questions

    Explore conceptually related problems

    Adding inert gas to system N_(2(g)) + 3H_(2(g))hArr2NH_(3(g)) at equilibrium at constant volume will be –

    PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) In given equilibrium reaction, volume of container is increased by mixing inert gas at constant temperature :

    The following two reactions: i. PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) (ii) COCl_(2)(g) hArr CO(g)+Cl_(2)(g) are simultaneously in equilibrium in a container at constant volume. A few moles of CO(g) are later introduced into the vessel. After some time, the new equilibrium concentration of

    For the reaction PCl _(5) (g) hArr PCl_(3)(g) + Cl_(2) (g), the forward reaction at constant temperature is favoured by

    For the reaction, PCl_(3)(g)+Cl_(2)(g) hArr PCl_(5)(g) , the position of equilibrium can be shifted to the right by: