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The ionization constant of acetic acid 1...

The ionization constant of acetic acid `1.74xx10^(-5)`. Calculate the degree of dissociation of acetic acid in its `0.05 M` solution. Calculate the concentration of acetate ion in the solution and its `pH`.

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To solve the problem, we need to follow these steps: ### Step 1: Write the dissociation equation for acetic acid. Acetic acid (CH₃COOH) dissociates in water as follows: \[ \text{CH}_3\text{COOH} \rightleftharpoons \text{CH}_3\text{COO}^- + \text{H}^+ \] ### Step 2: Set up the expression for the ionization constant (Ka). The ionization constant \( K_a \) is given by: ...
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The ionization constant of acetic acid is 1.74xx10^(-5) . Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ions in the solution and its pH .

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Knowledge Check

  • The ionisation constant of acetic acid is 1.74xx10^(-5) . The degree of dissociation of acetic acid in its 0.05 m solution and its pH are respectively

    A
    `1.86xx10^(-2), 4`
    B
    `1.24xx10^(-3), 4`
    C
    `1.24xx10^(-3), 3`
    D
    `1.86xx10^(-2), 3`
  • The degree of dissociation of acetic acid in a 0.1 M solution is 1.32xx10^(-2) , find out the pKa :-

    A
    5.75
    B
    3.75
    C
    4. 00
    D
    4. 75
  • The acid dissociation constant K_(a) of acetic acid is 1.74 xx 10^(-5) at 298 K. The pH of a solution of 0.1 M acetic acid is

    A
    2.88
    B
    3.6
    C
    `4.0`
    D
    `1.0`
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