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Calculate EMF of the following half cell...

Calculate `EMF` of the following half cells `:`
`a. Pt, H_(2)(2 atm)|HCl(0.02M)" "E^(c-)=0V`
`b. Pt , Cl_(2)(10 atm)|HCl(0.1 M)" "E^(-c)=1.36V`

Text Solution

AI Generated Solution

To calculate the EMF of the given half-cells, we will use the Nernst equation: \[ E = E^\circ - \frac{0.059}{n} \log Q \] Where: - \(E\) is the cell potential (EMF) ...
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Calculate pH of the half cell : Pt,H_(2)(1 atm)|H_(2)SO_(4)" "E^(c-)=-0.3V

Calculate the pH of the following half-cells solutions : (a) PtH_(2) ("1 atm")|H^(+) (HCl), " "E=0.25" volt" (b) PtH_(2) ("1 atm")|H^(+) (H_(2)SO_(4))," "E=0.3" volt"

Find the electrode potentials of the following electrodes. (a) Pt, H_2 (1 atm)/HCl (0.1 M), (b) Pt, H_2 (2 atm)/ H_2SO_4 (0.01 M)

The pH of LHE in the following cell is : Pt, H_(2)(1atm)|H^(o+)(x M)||H^(o+)(0.1M)|H_(2)(0.1atm)Pt E_(cell)=0.295V .

Calculate the e.m.f of the following cell : Cd|Cd^(2+) (0.01 M) ||H^(+) (0.02 M) |Pt , H_(2) (0.8 atm) Given : E^(@) (Cd^(2+) |Cd) = -0.40V

Calculate the potential of the following half - cells | cells : a. Cr|Cr^(3+)(0.1 M)||Fe^(2+)(0.01M)|Fe Given : E^(c-)._(Cr^(3+)|Cr)=-0.74V E^(c-)._(Fe^(2+)|Fe)=-0.44V b. 6e^(c-)+BrO_(3)^(c-)(aq)+3H_(2)OrarrBr^(c-)(aq)+6OH(aq) Given :E^(c-)._((BrO_(3)^(c-)|Br^(c-)))=0.61V, [BrO_(3)^(c-)]=2.5xx10^(-3)M,[Br^(c-)]=5.0xx10^(-3)M,pH=9.0 c. Ag|Ag^(o+)(0.1M)||Cl^(c-)(0.02M)|Cl_(2)(g)(0.5atm)|Pt Given E_((Ag^(o+)|Ag))=0.80V,E^(c-)((Cl_(2)|2Cl^(c-))=1.36V d. NO_(3) ^(c-)(aq)+2H^(o+)(aq)+e^(-)rarrNO_(2)+H_(2)O Given : E^(c-)._(NO_(3)^(c-)|NO_(2)=0.78V What will be the reductino potential of the half cell in neutral solution ? Assuming all the other species to be at unit concentration.

Knowledge Check

  • Calculate pH of the half cell : Pt,H_(2)(1 atm)|H_(2)SO_(4)" "E^(c-)=-0.3V

    A
    2
    B
    5
    C
    10
    D
    1

  • The pH of LHE in the following cell is : Pt, H_(2)(1atm)|H^(o+)(x M)||H^(o+)(0.1M)|H_(2)(0.1atm)Pt E_(cell)=0.295V .

    A
    `6.5`
    B
    `6.0`
    C
    `5.5`
    D
    `4.0`
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