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Calculate EMF of the following half cell...

Calculate `EMF` of the following half cells `:`
`a. Pt, H_(2)(2 atm)|HCl(0.02M)" "E^(c-)=0V`
`b. Pt , Cl_(2)(10 atm)|HCl(0.1 M)" "E^(-c)=1.36V`

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To calculate the EMF of the given half-cells, we will use the Nernst equation: \[ E = E^\circ - \frac{0.059}{n} \log Q \] Where: - \(E\) is the cell potential (EMF) ...
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