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Calculate EMF of the following half cell...

Calculate `EMF` of the following half cells `:`
`a. Pt, H_(2)(2 atm)|HCl(0.02M)" "E^(c-)=0V`
`b. Pt , Cl_(2)(10 atm)|HCl(0.1 M)" "E^(-c)=1.36V`

Text Solution

AI Generated Solution

To calculate the EMF of the given half-cells, we will use the Nernst equation: \[ E = E^\circ - \frac{0.059}{n} \log Q \] Where: - \(E\) is the cell potential (EMF) ...
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Calculate the emf of half cells given below: (a) pt, H_(2) HCI 2 atm, H^+ =0.02" " E_(op)^@=o V (b) pt, CI_(2) HCI 10 atm, CI^-=0.1 " " E_(op)^@=-1.36 V

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Knowledge Check

  • Calculate pH of the half cell : Pt,H_(2)(1 atm)|H_(2)SO_(4)" "E^(c-)=-0.3V

    A
    2
    B
    5
    C
    10
    D
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  • The pH of LHE in the following cell is : Pt, H_(2)(1atm)|H^(o+)(x M)||H^(o+)(0.1M)|H_(2)(0.1atm)Pt E_(cell)=0.295V .

    A
    `6.5`
    B
    `6.0`
    C
    `5.5`
    D
    `4.0`

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