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Aqueous AB(2) decomposes according to th...

Aqueous `AB_(2)` decomposes according to the first order reaction:
`AB_(2)(aq) rarr A(g) + 2B(l)`
After `20 min` the volume of `A(g) ` colledcted during such a reaction is `20 mL`, and that collected after a very long time is `40 mL`. The rate constant is :

A

`A. 3.45 xx 10^(-3) min^(-1)`

B

`B. 3.45 xx 10^(-2) min^(-1)`

C

`C. 1.435 xx 10^(-2) min^(-1)`

D

`D. 6.93 min^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(,AB_(2)(aq) ,underset("first order")rarr,A(g),2B(l)),(t=0,a,,0,0),(t=20 min,(a-x),,x,2x),(t=oo min,0,,a,2a):}`
Note: At constant `T` and `P`, mole `prop` pressure.
`:. x prop 20`
`alpha prop 40`
`:. k = (2.3)/(t)log.((a)/(a-x))`
`= (2.3)/(20 min) log. (40)/((40-20))`
`= (2.3)/(20) xx log2 = (2.3 xx 0.3)/(20) = 3.45 xx 10^(-2) min^(-1)`
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Knowledge Check

  • The compoistion of N_(2)O_(5) is a first order reaction represented by: N_(2)O_(5) rarr N_(2)O_(4) + 1//2O_(2) . After 20 min the volume of O_(2) profuced is 10 mL and at the end of the reaction 40 mL . The rate constant is equal to

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    `(1)/(20)ln.(30)/(50)`
    B
    `(1)/(20)ln.(50)/(30)`
    C
    `(1)/(20)ln.(50)/(40)`
    D
    `(1)/(20)ln.(40)/(30)`

  • For the first order reaction. N_2O_5(g) rightarrow N_2O_4(g) + 1/2 O_2 (g), the volume of O_2 produced is 15 mL and 40 mL after 8 minutes and at the end of the reaction respectively. The rate constant is equal to

    A
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    B
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    C
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    D
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    B
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    C
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    D
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