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The rate of first order reaction is 0.04...

The rate of first order reaction is `0.04 mol L^(-1) s^(-1)` at `10 min` and `0.03 mol L^(-1) s^(-1)` at `20 min` after initiation. Find the half life of the reaction.

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To find the half-life of the first-order reaction given the rates at two different times, we can follow these steps: ### Step 1: Understand the relationship between rate and concentration For a first-order reaction, the rate of reaction (R) is given by the equation: \[ R = k \cdot [A] \] where \( k \) is the rate constant and \([A]\) is the concentration of the reactant. ### Step 2: Set up the equations based on the given rates ...
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In a reaction with initially 0.12 M , the concentration of reactant is reduced to 0.06 M in 10 hour and to 0.03 M in 20 hour. (i) What is order of reaction? (ii) What is rate constant? (b) The rate of a first order reaction is 0.04 mol litre^(-1) s^(-1) at 10 minute and 0.30 mol litre^(-1) at 20 minute after initiation. Find the half-life of the reaction.

The rate of a first-order reaction is 0.04 mol L^(-1)s^(-1) at 10 seconds and 0.03 mol L^(-1)s^(-1) at 20 seconds after initiation of the reaction. The half-life period of the reaction is

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