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The density of silver having atomic ...

The density of silver having atomic mass 107. 9 u is 10.5 g`cm^(-3)`
If its crystalline structure is fcc find the edge length and radius of silver atom.

Text Solution

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408. pm , 144 pm
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The density of silver having atomic mass 107.8 gram "mol"^(-1) is 10.8 gram cm^(-3) . If the edge length of cubic unit cell is 4.05xx10^(-8)cm , find the number of silver atoms in the unit cell. (N_(A)=6.022xx10^(23),1A^(@)=10^(-8)cm)

Silver has atomic mass 108 a.m.u. and density 10.5 g cm^(-3) . If the edge length of its unit cell is 409 pm, identify the type of unit cell. Also calculate the radius of an atom of silver.

Knowledge Check

  • If the lattice parameter for a crystalline structure is 3.6 A , then the atomic radius in fcc crystal is

    A
    `1.27 A`
    B
    `1.81 A`
    C
    `2.10 A`
    D
    `2.92 A`
  • Silver metal crystallises in a cubic closed packed arrangement with edge length 404 pm .Thus radius of the silver atom is

    A
    `203.5` pm
    B
    `138.8` pm
    C
    `142.8` pm
    D
    `407.0` pm
  • The unit cell of an element having atomic mass 100 and density 12 g cm^(-3) is a cube with edge length 300 pm, the structure of crystal lattice is

    A
    fcc
    B
    bcc
    C
    simple cubic
    D
    None
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    The unit cell of a metallic element of atomic mass 10^(8) and density 10.5 g/cm^(3) is a cube with edge length of 409 PM. The structure of the crystal lattice is - (A) fcc (B) bcc (C) hcp (D) None of these

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