Home
Class 12
CHEMISTRY
A reaction has rate constants 1.73 xx...

A reaction has rate constants `1.73 xx 10^(-3) min^(-1) ` and `4.86 xx 10^(-3) min^(-1) ` at 300 K and 300 K respectively. Calculate
The energy of activation of the reaction
`(R= 8.314 JK^(-1) mol^(-1))`

Text Solution

Verified by Experts

Activation energy `=E_(a) = 28. 35 kJ`
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

The reaction C_(2)H_(5)I to C_(2)H_(4) + HI is of first order and its rate constants are 3.20 xx 10^(-4) s^(-1) at 600 K and 1.60 xx 10^(-2)s^(-1) at 1200 K. Calculate the energy of activation for the reaction. (Given R= 8.314 JK^(-1)mol^(-1))

The rate constant of a reaction is 1.5 xx 10^(7)s^(-1) at 50^(@) C and 4.5 xx 10^(7)s^(-1) at 100^(@) C. Calculate the value of activation energy for the reaction (R=8.314 J K^(-1)mol^(-1))

Knowledge Check

  • The rate constant for a reaction is 2xx10^(-2) s^(-1) at 300 K and 8xx10^(-2) s ^(-1) at 340 K The energy of activation of the reaction is

    A
    `14.695` kJ `"mol"^(-1)`
    B
    `29.39` kJ `"mol"^(-1)`
    C
    `44 kJ "mol"^(-1)`
    D
    `22 kJ "mol"^(-1)`
  • The rate coefficient (k) for a particular reactions is 1.3 xx 10^(-4)M^(-1)s^(-1) at 100^(@)C , and 1.3 xx 10^(-3)M^(-1)s^(-1) at 150^(@)C . What is the energy of activation ( E_(a) ) (in kJ) for this reaction? (R=molar gas constant = 8.314 JK^(-1) mol^(-1) )

    A
    16
    B
    60
    C
    99
    D
    132
  • A plot of "Ink "v//s " 1/T" for a reaction gives the slope -1xx10^(4)k. The energy of activation for the reaction is (Given,R=8.314k^(-1)" mol"^(-1))

    A
    `8314kJ" mol"^(-1)`
    B
    `1.202kJ" mol"^(-1)`
    C
    `1202kJ" mol"^(-1)`
    D
    `83.14kJ" mol"^(-1)`
  • Similar Questions

    Explore conceptually related problems

    For a decomposition, the values of rate constants at two different temperature are given below: k_(1) = 2.15 xx 10^(-8)L mol^(-1)s^(-1) at 650 K k_(2) = 2.39 xx 10^(-7) L mol^(-1)s^(-1) at 700 K Calculate the value of activation energy for the reaction (R= 8.314 JK^(-1) mol^(-1))

    If the rate constant of a reaction is 3.0 mol L^(-1)s^(-1) at 700 K and 30 mol L^(-1)s^(-1) at 800 K, what is the energy of activation for this reaction? R = 8.314 JK^(-1) mol^(-1)

    The rate of a reaction increases four times when the temperature changes from 300K to 320 K. Calculate the energy of activation of the reaction. (R=8.314JK^(-1)mol^(-1))

    The decomposition of phosphine, 4PH_(3)(g) to P_(4)(g) + 6H_(2)(g) has rate law , Rate = k[PH_(3)] . The rate constant is 6.0 xx 10^(-4) s^(-1) at 300 K and activation energy is 3.05 xx 10^(5) J mol^(-1) . Calculate the value of the rate constant at 310 K ( R= 8.314 JK^(-1)mol^(-1))

    For a decomposition reaction, the values of rate constant k at two different temmperature are given below: k_(1)=2.15xx10^(-8)"L mol"^(-1)s^(-1) at 650 K k_(2)=2.39xx10^(-7)"L mol"^(-1)s^(-1) at 700 K Calculate the value of activation energy for this reaction. [R=8.314JK^(-1)"mol"^(-1)]