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If P is the pressure of gas, then the ki...

If `P` is the pressure of gas, then the kinetic energy per unit volume of the gas is .

Text Solution

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According to the kinetic theory of an ideal gas, the pressure p exerted by the gas is given by
`p=(1)/(3)rhoc^(2)_(rms)=(1)/(3)(m)/(V)c^(2)_(rms)`
where `c_(rms)` is the rms speed (root-maen-square speed) of the gas molecules,m, V and `rho` are the mass, volume and density of the gas, respectively.
`:. pV=(1)/(3)mc^(2)_(rms)=(2)/(3)((1)/(2)mc^(2)_(rms))`
Here,`(1)/(2)mc^(2)_(rms)` is the total kinetic energy (KE) of all molecules of the gas.
`:. pV=(2)/(3)(KE)" " :. KE=(3)/(2)pV" " :. (KE)/(V)=(3)/(2)p`
Thus, the kinetic energy per unit volume of a gas is `(3)/(2)`p.
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Knowledge Check

  • Kinetic energy per unit volume of a gas is

    A
    `(3P)/2`
    B
    `(2P)/3`
    C
    `P/2`
    D
    `P/3`
  • If P is the pressure of gas then translational kinetic energy per unit volume of the gas is

    A
    `(P)/(2)`
    B
    P
    C
    `(3)/(2)P`
    D
    2P
  • Kinetic energy per mole of an ideal gas is :

    A
    directly proportional to its absolute temperature.
    B
    inversely proportional to its absolute temperature.
    C
    independent of temperatuer.
    D
    zero at `0^(@)C`.
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