Home
Class 12
CHEMISTRY
Express the terms representing the follo...

Express the terms representing the following formulae .
(i)`"No. of moles of solute"/"Volume of solution in litres"=(W)`
(ii)`"No. of moles of solute"/"Mass of solvent in kg"=(X)`
(iii)`"No. of moles of component"/"Moles in the solution"=(Y)`
(iv)`"Mass of component"/"Mass of solution"=(Z)`

A

W-Molality , X-Molarity , Y-Mass fraction, Z-Mole fraction

B

W-Molarity , X-Molality , Y-Mass fraction, Z-Mole fraction

C

W-Molarity , X-Molality , Y-Mole fraction, Z-Mass fraction

D

W-Molality , X-Molarity , Y-Mass fraction, Z-Mass fraction

Text Solution

Verified by Experts

The correct Answer is:
C
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOLUTIONS

    NCERT FINGERTIPS|Exercise Solubility|11 Videos

  • SOLUTIONS

    NCERT FINGERTIPS|Exercise Vapour Pressure Of Liquid Solutions|5 Videos

  • SOLUTIONS

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

  • PRACTICE PAPER -3

    NCERT FINGERTIPS|Exercise Practice Paper 3|50 Videos

  • SURFACE CHEMISTRY

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

Match the terms given in Column I with expressions given in Column II. {:("Column I","Column II"),("(i) Mass percentage","(a) "("Number of moles of the solute component")/("Volume of solution in litres")),("(ii) Volume percentage","(b) "("Number of moles of a component")/("Total number of moles of all the components")),("(iii) Mole fraction","(c) "("Volume of the solute component in solution")/("Total volume of solution")xx100),("(iv) Molality ","(d) "("Mass of the solute component in solution")/("Total mass of the solution")xx100),("(v) Molarity","(e) "("Number of moles of the solute coponents")/("Mass of solvent in kilograms")):}

The sum of mole fraction of all components of a solution is unity.

Knowledge Check

  • Express the terms representing are following formulae : (i) (No. of moles of solute)/(Volume of solution in litres)=P (ii) (No. of moles of solute)/(Mass of solvent in kg )=Q iii. (No. of moles of component)/(Moles in the solution ) =R iv. (Mass of component)/(Mass of solution)=S

    A
    Molality ,Molarity,Mass fraction,Mole fracton
    B
    Molarity, Molality , Mass fraction ,Mole fraction
    C
    Molarity,Molality , Mole fraction,Mass fraction
    D
    Molality , Molarity ,Mole fraction,Mass fraction

  • Number of moles of solute dissolved per litre of solution is

    A
    normality
    B
    molarity
    C
    molality
    D
    none of these

  • The number of mole of solute per litre solution is called

    A
    Molality
    B
    Normality
    C
    Molarity
    D
    Mole fraction

    • Similar Questions

    Explore conceptually related problems

    The sum of the mole fraction of the components of a solution is

    When the concentration is expressed as the number of moles of a solute per litre of solution it is known as

    Number of moles of a solute per kilogram of a solvent is called

    Sum of mole fractions of the two components of a solution is

    The number of moles of solute per kg of a solvent is called its :

    Home
    Profile