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The reaction 2NO + Br(2) to 2NOBr, obeys...

The reaction `2NO + Br_(2) to 2NOBr`, obeys the following mechanism:
`NO + Br_(2) overset("fast")(hArr) NOBr_(2), NOBr_(2) + NO overset("Slow")(to) 2NOBr` The rate expression of the above reaction can be written as

A

`r = k [NO]^(2) [Br_(2)]_(2)`

B

`r = k [NO][Br_(2)]`

C

`r = k [NO][Br_(2)]`

D

`r = k [NOBr_(2)]`

Text Solution

Verified by Experts

The correct Answer is:
A

For slowest step : rate `= k [NOBr_(2)][NO]` …(i)
For equilibrium also `K_(c ) = ([NOBr_(2)])/([NO][Nr_(2)])`
Rate `= k [NO]^(2) [Br_(2)]`
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